Route from Stevenage to South Oxfordshire by car

From: Stevenage, County: Hertfordshire, England
To: South Oxfordshire, County: Oxfordshire, England
63 mi
1 h 9 min
Fuel consumption:
Fuel cost:
Passengers:



How many miles from Stevenage to South Oxfordshire?

How far is from Stevenage to South Oxfordshire?


The driving distance between Stevenage and South Oxfordshire is 63 miles. Travel time is 1 hour and 9 minutes by car.






63 mi 1 h 9 min
1.
Head south on Silam Road
732 ft
2.
Turn right onto Cuttys Lane
437 ft
3.
Turn left onto St George's Way (A1155)
918 ft
4.
Enter the roundabout and take the 2nd exit onto Monkswood Way (A602)
204 ft
5.
Exit the roundabout onto Monkswood Way (A602)
0.6 mi
6.
Enter the roundabout and take the 3rd exit onto Broadhall Way (A602)
306 ft
7.
Exit the roundabout onto Broadhall Way (A602)
0.3 mi
8.
Enter Broadhall Way and take the 2nd exit onto Broadhall Way (A602)
189 ft
9.
Exit the roundabout onto Broadhall Way (A602)
886 ft
10.
Enter Langley Sidings and take the 2nd exit onto A1(M)
76 ft
11.
Exit the roundabout onto A1(M)
9.7 mi
12.
Take the ramp on the left towards A414: St Albans
0.3 mi
13.
Enter Roehyde Interchange and take the 2nd exit onto North Orbital Road (A414)
599 ft
14.
Exit the roundabout onto North Orbital Road (A414)
1.2 mi
15.
Keep left onto North Orbital (A414)
1.7 mi
16.
Enter London Colney Roundabout and take the 3rd exit onto North Orbital Road (A414)
455 ft
17.
Exit the roundabout onto North Orbital Road (A414)
1.9 mi
18.
Enter Park Street Roundabout and take the 2nd exit onto North Orbital Road (A405)
198 ft
19.
Exit the roundabout onto North Orbital Road (A405)
0.6 mi
20.
Enter the roundabout and take the 2nd exit onto North Orbital Road (A405)
106 ft
21.
Exit the roundabout onto North Orbital Road (A405)
0.6 mi
22.
Enter the roundabout and take the 1st exit onto North Orbital Road (A405)
130 ft
23.
Exit the roundabout onto North Orbital Road (A405)
0.4 mi
24.
Enter Bricket Wood Junction and take the 3rd exit towards M25: Heathrow
583 ft
25.
Exit the roundabout towards M25: Heathrow
0.5 mi
26.
Merge right onto M25
14.4 mi
27.
Take the ramp on the left towards M40: Birmingham
21.9 mi
28.
Take the ramp on the left towards B4009
0.3 mi
29.
Turn left onto Oakley Road (B4009)
0.2 mi
30.
Continue onto Watlington Road (B4009)
1.8 mi
31.
Continue onto Shirburn Road (B4009)
0.3 mi
32.
Continue onto Shirburn Street (B4009)
776 ft
33.
Continue left onto Couching Street (B4009)
800 ft
34.
Turn right onto B480
860 ft
35.
Keep left onto Britwell Road (B4009)
3.1 mi
36.
Go straight onto The Sands (B4009)
0.8 mi
37.
Turn right
0.5 mi
38.
Make a slight left
466 ft
39.
You have arrived at your destination, on the right
1 ft



How much does it cost to drive from Stevenage to South Oxfordshire?

The fuel cost by car depend on several factors such as the distance traveled, the driving conditions (traffic jam, slow driving, normal driving, race driving), fuel consumption of the vehicle, and the current price of fuel.

The trip with petrol fuel costs 10.9 £. In the above calculation, the petrol price is considered to be 143 pence per liter and the petrol consumption of the car is 37.5 miles per gallon.
For 2 passengers in carpooling, the cost of this trip is 5.45 £ (10.9/2) per passenger.
For 3 passengers in the car, the cost of this trip is 3.63 £ (10.9/3) per passenger.
For 4 passengers in the car, the cost of this trip are 2.73 £ (10.9/4) per passenger.


Fuel cost = (62.9 mi / 37.5 mpg) x 143 pence per liter = 10.9 £

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles * 4.54609 / carConsumtion = 62.9 mi * 4.54609 / 37.5 mpg = 7.6 liters

Fuel needed = 7.6 lt

Fuel cost = Fuel needed x Price per liter = 7.6 liters x 143 pence per liter = 10.9 £

Fuel cost from Stevenage to South Oxfordshire = 10.9 £

Why do I multiply miles by 4.54609?

Consumption is measured in miles per gallon. 37.5 mpg means that a car could travel 37.5 miles with a gallon petrol fuel. The price of fuel is in pence per liter. Gallons should be converted to liters so that the final fuel consumption on a trip is in liters. 1 gallon is 4.54609 liters, so multiply by 4.54609.


The trip with diesel fuel costs 6.9 £. In the above calculation, the diesel price is considered to be 151 pence per liter and the diesel consumption of the car is 62.7 mpg. For only one passenger the cost of the trip is 6.9 £.
For 2 passengers in carpooling, the cost of this trip is 3.45 £ (6.9/2) per passenger.
For 3 passengers in the car, the cost of this trip is 2.3 £ (6.9/3) per passenger.
For 4 passengers in the car, the cost of this trip is 1.73 £ (6.9/4) per passenger.