Route from Stevenage to West Lancashire by car

From: Stevenage, County: Hertfordshire, England
To: West Lancashire, County: Lancashire, England
189 mi
3 h 18 min
Fuel consumption:
Fuel cost:
Passengers:



How many miles from Stevenage to West Lancashire?

How far is from Stevenage to West Lancashire?


The driving distance between Stevenage and West Lancashire is 189 miles. Travel time is 3 hours and 18 minutes by car.






189 mi 3 h 18 min
1.
Head north on Silam Road
660 ft
2.
Turn left onto Fairlands Way (A1155)
678 ft
3.
Enter the roundabout and take the 2nd exit onto Fairlands Way (A1155)
269 ft
4.
Exit the roundabout onto Fairlands Way (A1155)
0.2 mi
5.
Enter the roundabout and take the 3rd exit onto Lytton Way (A602)
430 ft
6.
Exit the roundabout onto Lytton Way (A602)
935 ft
7.
Enter the roundabout and take the 2nd exit onto Lytton Way (A602)
272 ft
8.
Exit the roundabout onto Lytton Way (A602)
0.5 mi
9.
Keep left onto Hitchin Road (A602)
986 ft
10.
Keep right onto A602
205 ft
11.
Keep left onto A602
0.4 mi
12.
Enter the roundabout and take the 2nd exit onto Hitchin Road (A602)
142 ft
13.
Exit the roundabout onto Hitchin Road (A602)
0.4 mi
14.
Enter Corey's Mill and take the 2nd exit onto A602
405 ft
15.
Exit the roundabout onto A602
2.7 mi
16.
Enter the roundabout and take the 3rd exit onto Park Way (A602)
308 ft
17.
Exit the roundabout onto Park Way (A602)
0.6 mi
18.
Enter the roundabout and take the 1st exit onto Upper Tilehouse Street (A505)
18 ft
19.
Exit the roundabout onto Upper Tilehouse Street (A505)
801 ft
20.
Turn right onto Pirton Road (B655)
4 mi
21.
Continue onto Barton Road (B655)
1.2 mi
22.
Continue onto Hexton Road (B655)
1.2 mi
23.
Turn left to stay on Hexton Road (B655)
76 ft
24.
Turn right onto Luton Road (B655)
522 ft
25.
Turn left onto Sharpenhoe Road
0.5 mi
26.
Continue onto Barton Road
0.6 mi
27.
Continue onto Harlington Road
1.3 mi
28.
Turn right
0.3 mi
29.
Continue onto Barton Road
0.4 mi
30.
Continue onto Church Road
1049 ft
31.
Continue onto Station Road
746 ft
32.
Continue onto Toddington Road
0.7 mi
33.
Enter the roundabout and take the 1st exit onto Harlington Road (A5120)
80 ft
34.
Exit the roundabout onto Harlington Road (A5120)
0.6 mi
35.
Take the ramp on the right towards M1: The_NORTH
0.5 mi
36.
Merge right onto M1
43 mi
37.
Take the ramp on the left towards M6: The N. WEST
22.8 mi
38.
Keep left onto M6
14.2 mi
39.
Keep right onto M6
7.9 mi
40.
Keep right onto M6
72 mi
41.
Keep right onto M6
2.7 mi
42.
Take the ramp on the left onto M6
0.4 mi
43.
Enter Orrell Interchange and take the 1st exit onto M58
31 ft
44.
Exit the roundabout onto M58
5.2 mi
45.
Take the ramp on the left
0.3 mi
46.
Enter Bickerstaffe Interchange and take the 3rd exit onto Rainford Road (A570)
918 ft
47.
Exit the roundabout onto Rainford Road (A570)
585 ft
48.
Enter the roundabout and take the 2nd exit onto Lyelake Lane (B5240)
233 ft
49.
Exit the roundabout onto Lyelake Lane (B5240)
1.3 mi
50.
Turn left onto Wigan Road (A577)
0.7 mi
51.
Turn right onto Castle Lane
0.9 mi
52.
Continue left onto Lathom Lane
682 ft
53.
Turn left
1056 ft
54.
You have arrived at your destination, on the left
0 ft



How much does it cost to drive from Stevenage to West Lancashire?

The fuel cost by car depend on several factors such as the distance traveled, the driving conditions (traffic jam, slow driving, normal driving, race driving), fuel consumption of the vehicle, and the current price of fuel.

The trip with petrol fuel costs 32.8 £. In the above calculation, the petrol price is considered to be 143 pence per liter and the petrol consumption of the car is 37.5 miles per gallon.
For 2 passengers in carpooling, the cost of this trip is 16.4 £ (32.8/2) per passenger.
For 3 passengers in the car, the cost of this trip is 10.93 £ (32.8/3) per passenger.
For 4 passengers in the car, the cost of this trip are 8.2 £ (32.8/4) per passenger.


Fuel cost = (189.39 mi / 37.5 mpg) x 143 pence per liter = 32.8 £

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles * 4.54609 / carConsumtion = 189.39 mi * 4.54609 / 37.5 mpg = 23 liters

Fuel needed = 23 lt

Fuel cost = Fuel needed x Price per liter = 23 liters x 143 pence per liter = 32.8 £

Fuel cost from Stevenage to West Lancashire = 32.8 £

Why do I multiply miles by 4.54609?

Consumption is measured in miles per gallon. 37.5 mpg means that a car could travel 37.5 miles with a gallon petrol fuel. The price of fuel is in pence per liter. Gallons should be converted to liters so that the final fuel consumption on a trip is in liters. 1 gallon is 4.54609 liters, so multiply by 4.54609.


The trip with diesel fuel costs 20.7 £. In the above calculation, the diesel price is considered to be 151 pence per liter and the diesel consumption of the car is 62.7 mpg. For only one passenger the cost of the trip is 20.7 £.
For 2 passengers in carpooling, the cost of this trip is 10.35 £ (20.7/2) per passenger.
For 3 passengers in the car, the cost of this trip is 6.9 £ (20.7/3) per passenger.
For 4 passengers in the car, the cost of this trip is 5.18 £ (20.7/4) per passenger.