Route from Sandwell to South Oxfordshire by car

From: Sandwell, County: West Midlands, England
To: South Oxfordshire, County: Oxfordshire, England
95 mi
1 h 42 min
Fuel consumption:
Fuel cost:
Passengers:



How many miles from Sandwell to South Oxfordshire?

How far is from Sandwell to South Oxfordshire?


The driving distance between Sandwell and South Oxfordshire is 95 miles. Travel time is 1 hour and 42 minutes by car.






95 mi 1 h 42 min
1.
Head south on Hill Top (A4196)
928 ft
2.
Continue onto Black Lake (A4196)
0.3 mi
3.
Continue onto Old Meeting Street (A4196)
0.3 mi
4.
Enter Albion Roundabout and take the 1st exit onto The Expressway (A41)
74 ft
5.
Exit the roundabout onto The Expressway (A41)
1.6 mi
6.
Enter West Bromwich Interchange and take the 4th exit
1135 ft
7.
Exit the roundabout
1108 ft
8.
Merge right onto M5
12.6 mi
9.
Take the ramp on the left onto M42
0.6 mi
10.
Keep left onto M42
10.6 mi
11.
Keep right onto M40
0.3 mi
12.
Keep right towards London
56.7 mi
13.
Take exit 8A on the left towards A418: Oxford Services
0.3 mi
14.
Enter the roundabout and take the 1st exit onto A418
137 ft
15.
Exit the roundabout onto A418
0.6 mi
16.
Turn right to stay on London Road (A40)
1.5 mi
17.
Make a sharp right onto A329
2.7 mi
18.
Make a slight right onto Church Hill (A329)
922 ft
19.
Continue onto Stadhampton Road (A329)
1.1 mi
20.
Continue onto Milton Road (A329)
0.4 mi
21.
Continue slightly right onto Thame Road (A329)
0.3 mi
22.
Turn left onto Newington Road (A329)
1.7 mi
23.
Turn left
1.6 mi
24.
Keep left at the fork
89 ft
25.
Continue straight
0.5 mi
26.
Make a sharp right
432 ft
27.
You have arrived at your destination, on the right
1 ft



How much does it cost to drive from Sandwell to South Oxfordshire?

The fuel cost by car depend on several factors such as the distance traveled, the driving conditions (traffic jam, slow driving, normal driving, race driving), fuel consumption of the vehicle, and the current price of fuel.

The trip with petrol fuel costs 16.4 £. In the above calculation, the petrol price is considered to be 143 pence per liter and the petrol consumption of the car is 37.5 miles per gallon.
For 2 passengers in carpooling, the cost of this trip is 8.2 £ (16.4/2) per passenger.
For 3 passengers in the car, the cost of this trip is 5.47 £ (16.4/3) per passenger.
For 4 passengers in the car, the cost of this trip are 4.1 £ (16.4/4) per passenger.


Fuel cost = (94.75 mi / 37.5 mpg) x 143 pence per liter = 16.4 £

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles * 4.54609 / carConsumtion = 94.75 mi * 4.54609 / 37.5 mpg = 11.5 liters

Fuel needed = 11.5 lt

Fuel cost = Fuel needed x Price per liter = 11.5 liters x 143 pence per liter = 16.4 £

Fuel cost from Sandwell to South Oxfordshire = 16.4 £

Why do I multiply miles by 4.54609?

Consumption is measured in miles per gallon. 37.5 mpg means that a car could travel 37.5 miles with a gallon petrol fuel. The price of fuel is in pence per liter. Gallons should be converted to liters so that the final fuel consumption on a trip is in liters. 1 gallon is 4.54609 liters, so multiply by 4.54609.


The trip with diesel fuel costs 10.4 £. In the above calculation, the diesel price is considered to be 151 pence per liter and the diesel consumption of the car is 62.7 mpg. For only one passenger the cost of the trip is 10.4 £.
For 2 passengers in carpooling, the cost of this trip is 5.2 £ (10.4/2) per passenger.
For 3 passengers in the car, the cost of this trip is 3.47 £ (10.4/3) per passenger.
For 4 passengers in the car, the cost of this trip is 2.6 £ (10.4/4) per passenger.